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Qus: What will be the output of the following Python code? <pre class="de1" style="border-radius: 0px; padding: 0px; font-family: Consolas, Monaco, " lucida="" console",="" monospace;="" color:="" rgb(51,="" 51,="" 51);="" word-break:="" break-all;="" overflow-wrap:="" normal;="" background:="" rgb(244,="" 244,="" 244);="" border:="" 0px;="" overflow:="" visible;="" box-shadow:="" none;="" text-align:="" justify;="" margin-top:="" 0px="" !important;="" margin-bottom:="" line-height:="" 20px="" !important;"="">places = ['Bangalore', 'Mumbai', 'Delhi'] places1 = places places2 = places[:] places1[1]="Pune" places2[2]="Hyderabad" print(places) </pre>

Qusनिम्नलिखित Python कोड का आउटपुट क्या होगा?<pre class="de1" lucida="" console",="" monospace;="" color:="" rgb(51,="" 51,="" 51);="" word-break:="" break-all;="" overflow-wrap:="" normal;="" background:="" rgb(244,="" 244,="" 244);="" border:="" 0px;="" overflow:="" visible;="" box-shadow:="" none;="" text-align:="" justify;="" margin-top:="" 0px="" !important;="" margin-bottom:="" line-height:="" 20px="" !important;"="" style="font-size: 12.6px; letter-spacing: 0.14px; border-radius: 0px; padding: 0px;">places = ['Bangalore', 'Mumbai', 'Delhi'] places1 = places places2 = places[:] places1[1]="Pune" places2[2]="Hyderabad" print(places)</pre>

A. [‘Bangalore’, ‘Pune’, ‘Hyderabad’]
B. [‘Bangalore’, ‘Pune’, ‘Delhi’]
C. [‘Bangalore’, ‘Mumbai’, ‘Delhi’]
D. [‘Bangalore’, ‘Mumbai’, ‘Hyderabad’]

Solution

B. [‘Bangalore’, ‘Pune’, ‘Delhi’]

Explanation

places1 is an alias of the list places. Hence, any change made to places1 is reflected in places. places2 is a copy of the list places. Thus, any change made to places2 isn’t reflected in places.